8m-64m^2+96m=0

Solution for 8m-64m^2+96m=0 equation:

8m-64m^2+96m=0

We add all the numbers together, and all the variables

-64m^2+104m=0

a = -64; b = 104; c = 0;
Δ = b2-4ac
Δ = 1042-4·(-64)·0
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(104)-104}{2*-64}=\frac{-208}{-128}
=1+5/8
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(104)+104}{2*-64}=\frac{0}{-128}
=0
$